read_connect(); //$GLOBALS[ezoic_db]->read->query("use 17things"); ?>

What is this question asking and how do I get there?

[OH-] = 8.2 x 10^-6 M

Is it asking for the pOH and pH? If so, can you give me in depth directions on how to get the answer?

Thanks!

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One Response to “What is this question asking and how do I get there?”

  1. Sweet said :

    I can’t be bothered doing the maths as you can do them yourself but here’s everything you need to know.

    pH + pOH = 14
    Thus the pH = 14 – pOH

    pOH = -log[OH] (log to the base 10).

    Calculate the pOH
    Subtract it from 14 to get the pH




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