What is this question asking and how do I get there?
[OH-] = 8.2 x 10^-6 M
Is it asking for the pOH and pH? If so, can you give me in depth directions on how to get the answer?
Thanks!
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December 7th, 2010 at 10:30 am
I can’t be bothered doing the maths as you can do them yourself but here’s everything you need to know.
pH + pOH = 14
Thus the pH = 14 – pOH
pOH = -log[OH] (log to the base 10).
Calculate the pOH
Subtract it from 14 to get the pH