## How do you find the x, y and z intercepts of a plane?

I have the below solid geometry problem. I do not know how to find the x, y and z intercepts of a plane. The answer to this would be nice but I what I really need is to understand how to do this.

The plane 2x + 3y – 4z = 5 intersects the x axis at (a,0,0), (0,b,0), (0,0,c). The value of a + b + c is?

Thanks.

November 29th, 2010 at 7:32 am

The intercepts occur when the other 2 coordinates are 0. To find the x-intercept, just set y and z equal to 0, and vice versa.

2a = 5

a = 5/2

3b = 5

b = 5/3

-4c = 5

c = -5/4

and I trust you can add them?

November 29th, 2010 at 8:26 am

For intercepts, you simply put 0 for the other two coordinates. Then:

a = 5/2

b = 5/3

c = -5/4

November 29th, 2010 at 8:58 am

(200)

(030)

(00-4) is you matrix coordinate.

It is supposed to intersect at +5.