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How do you find the x, y and z intercepts of a plane?

I have the below solid geometry problem. I do not know how to find the x, y and z intercepts of a plane. The answer to this would be nice but I what I really need is to understand how to do this.

The plane 2x + 3y – 4z = 5 intersects the x axis at (a,0,0), (0,b,0), (0,0,c). The value of a + b + c is?

Thanks.

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3 Responses to “How do you find the x, y and z intercepts of a plane?”

  1. Anon E. Moose said:

    The intercepts occur when the other 2 coordinates are 0. To find the x-intercept, just set y and z equal to 0, and vice versa.

    2a = 5
    a = 5/2

    3b = 5
    b = 5/3

    -4c = 5
    c = -5/4

    and I trust you can add them?

  2. Babipup said:

    For intercepts, you simply put 0 for the other two coordinates. Then:

    a = 5/2
    b = 5/3
    c = -5/4

  3. Ca Hena said:

    (200)
    (030)
    (00-4) is you matrix coordinate.
    It is supposed to intersect at +5.




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